Find the root of quadratic equation using C

A quadratic equation is a second-order polynomial equation in a single variable x with ax²+bx+c=0, a!=0.

The Quadratic Formula uses the "a", "b", and "c" from "ax² + bx + c", where "a", "b", and "c" are just numbers; they are the "numerical coefficients" of the quadratic equation they've given you to solve.

The Quadratic Formula is derived from the process of completing the square, and is formally stated as:

For ax² + bx + c = 0, the value of x is given by:

x  =  [ -b ± sqrt(b² - 4ac) ] / 2a

Because it is a second-order polynomial equation, the fundamental theorem of algebra guarantees that it has two solutions. These solutions may be both real, or both complex.

For Example Code:

File name : qurdation.c

   


#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
 float a,b,c,d,x1=0,x2=0;
 clrscr();
 printf("Enter the value of A:=");
 scanf("%f",&a);
 printf("Enter the value of B:=");
 scanf("%f",&b);
 printf("Enter the value of C:=");
 scanf("%f",&c);
 d=((b*b)-(4*a*c));
 clrscr();
 printf("\n|  A  | %.2f ",a);
 printf("\n|  B  | %.2f ",b);
 printf("\n|  C  | %.2f ",c);
 printf("\n-----------------");
 printf("\n|  D  | %.2f",d);
 if(d==0)
 {
  printf("\n\n|  Roots are real and equal");
  x1=((-b+sqrt(d))/(2*a));
  x2=((-b-sqrt(d))/(2*a));
 }
 else if(d>0)
 {
  printf("\n\n|  Roots are real and distict");
  x1=((-b+sqrt(d))/(2*a));
  x2=((-b-sqrt(d))/(2*a));
 }
 else if(d<0)
 {
  printf("\n\n|  Roots are imegnand  ");
 }
 printf("\n\n|  Value of X1 | %.2f",x1);
 printf("\n|  Value of X2 | %.2f",x2);
 getch();
}